Fractional Precipitation Pogil Answer Key 2021 -

Ksp = [Ag⁺][Cl⁻] → [Ag⁺] = Ksp / [Cl⁻]

[Ag+]=1.2×10-11=3.46×10-6 Mopen bracket Ag raised to the positive power close bracket equals the square root of 1.2 cross 10 to the negative 11 power end-root equals 3.46 cross 10 to the negative 6 power M Therefore,

For AgI precipitation: [Ag⁺] = Ksp / [I⁻] = (8.5 × 10⁻¹⁷) / 0.020 = 4.25 × 10⁻¹⁵ M fractional precipitation pogil answer key 2021

For AgI (1:1 salt): [I⁻] needed = Ksp / [Ag⁺] = (8.5 × 10⁻¹⁷) / 0.10 = 8.5 × 10⁻¹⁶ M

1.8×10-10=[Ag+](0.10 M)1.8 cross 10 to the negative 10 power equals open bracket Ag raised to the positive power close bracket open paren 0.10 M close paren Ksp = [Ag⁺][Cl⁻] → [Ag⁺] = Ksp / [Cl⁻] [Ag+]=1

(Ksp changes with temperature, often nonlinearly. The 2021 activity might have included a Van’t Hoff plot for this reason.)

POGIL models often ask: "What is the concentration of the first ion remaining in solution when the second ion just begins to precipitate?" Quick Summary Table Small Kspcap K sub s

POGIL activities are structured to build "mental models." If you skip to the answer key, you might miss the subtle logic required for advanced Equilibrium problems on exams like the AP Chemistry or General Chemistry II finals. Most instructors use the 2021 version specifically because it clarifies the relationship between molar solubility and the Kspcap K sub s p end-sub comparison. Quick Summary Table Small Kspcap K sub s p end-sub Less soluble, precipitates earlier. Large Kspcap K sub s p end-sub More soluble, stays in solution longer. Kspcap K sub s p end-sub Precipitation starts the moment Kspcap K sub s p end-sub

Find the concentration of the added ion needed to start the second precipitation. Step B: Plug that concentration back into the Kspcap K sub s p end-sub