Codehs 8.1.5 Manipulating 2d Arrays Upd -

System.out.println();

array[row].length gives you the number of in that specific row. 3. Conditional Logic (If-Statements)

Use the assignment operator ( = ) to update the element at [row][col] . Codehs 8.1.5 Manipulating 2d Arrays

To find the total count for the second row's requirement, you’ll need a nested for loop . The outer loop iterates through the rows ( array.length ).

Note: If your 2D array uses ArrayList<ArrayList<Integer>> , you’ll need a deep swap, but for standard [][] , this works perfectly. System

In 8.1.5, you’ll likely encounter a few specific ways to alter your data: Replacing Values:

for (int row = 0; row < matrix.length; row++) for (int col = 0; col < matrix[row].length; col++) // Manipulate matrix[row][col] here Use code with caution. 2. Modifying Specific Values To find the total count for the second

for (int row = 0; row < grid.length; row++) for (int col = 0; col < grid[row].length; col++) // Multiply every element by 2 grid[row][col] = grid[row][col] * 2; Use code with caution. Nested for-each Loops (Reading Data)

Manipulation usually requires a check. For example, if you are asked to change all even numbers to zero, you would use the modulo operator ( % ) inside your nested loops: if (array[row][col] % 2 == 0) array[row][col] = 0; Use code with caution. Common Pitfalls to Avoid

Modifying only elements that meet a certain condition, such as changing all negative numbers to zero.